Solve for x Use the distributive property to multiply xy by x^ {2}xyy^ {2} and combine like terms Use the distributive property to multiply x y by x 2 − x y y 2 and combine like terms Subtract x^ {3} from both sides Subtract x 3 from both sides Combine x^ {3} and x^ {3} to get 0 Combine x 3 and − x 3 to get 0Calculadoras gratuitas paso por paso para álgebra, Trigonometría y cálculo Simplify ((x^2 y^3 z^(2) )^(3) (x^(3) yz^3 )^(1/2))/(xyz^(3) )^(5/2) Latest Problem Solving in Fundamentals in Algebra More Questions in Fundamentals in Algebra Online Questions and Answers in Fundamentals in Algebra Series
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Expand and simplify (x+y)^3-Calculadoras gratuitas paso por paso para álgebra, Trigonometría y cálculo This answer has been confirmed as correct and helpful Simplify 2x x 2x² 3x 3x ² User Simplify 3x 3 2 3x 5 5x 3 8x Weegy 3x 3 2 = 3x 5 User Simplify 4 (N 9) 4N 9 4N 9 4N 36 Weegy 4 (N 9) is equal to 4N36
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Simplify {〖x^(2/3) x^(1/3) y^(1/2) (x^2 y^(2) )^(2/3) 〗^(1/2) }^6Simplify \frac{z}{3}y^{3}\frac{x}{3}\frac{z}{3}y^{3}\frac{x}{3} he Related Symbolab blog posts My Notebook, the Symbolab way Math notebooks have been around for hundreds of years You write down problems, solutions and notes to go backSimplify an expression Example (x^2y^2)/(xy) That is the reason the x 3 term was missing or not written in the original expression Solution Step 1 Arrange both the divisor and dividend in descending powers of the variable (this means highest exponent first, next highest second, and so on) and supply a zero coefficient for any missing
1) Simplify (Y^4) (y^3) Ay^1 By^7 (my answer) Cy^12 Dy^43 2)Simplify Y^6 / y^2 A y^8 B y^4 C y^3 ( my answer) D y^1 3 Convert into a fraction 5^3 A 1/5 B1/15 (my answer) C1/25 D1/125 4 15^0=?The simplified rational expression has just a constant in the denominator But the original complex rational expression had denominators of y−3 and \(y^2−9\) This expression would be undefined if y=3 or y=−3A0 (my answer) B1 C15 D1/15 5 Select all the expressions that are equivalent to y^4 A(y^2) (y^2)******(my answer) By^6 / y^2 Cy^0 Dy^9 / y^5******(my answer) E(y^4) (y^1
Add the two equivalent fractions which now have a common denominator Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible 3 • x (3 • y) 3x 3y ——————————————— = ——————— yx yxFirst week only $499!Simplify (xy)^3 (x − y)3 ( x y) 3 Use the Binomial Theorem x3 3x2(−y) 3x(−y)2 (−y)3 x 3 3 x 2 ( y) 3 x ( y) 2 ( y) 3 Simplify each term Tap for more steps Rewrite using the commutative property of multiplication
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